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=1/2×(15×10)
=1/2×150
=75
T0 = 28 C
L0 = 50 cm
L = 50,012 CM
α = 0,000012/C
dit : T ?
maka :
ΔT = ΔL/L0xα
(T-28) = (50,012-50) / 50 x 0,000012
(T-28) = 0,012/0,0006
T-28 = 20
T = 20+28
T = 48 C