Question

Carilah titik potong kurva; Y= 16-x2 dengan Y=4+X

Answer 1

16 - x² = 4 + x
0 = x² + x -12
0 = (x-3)(x+4)
x = 3 atau x = -4
jika x = 3 maka y = 4 + 3 = 7
   x = -4 maka y = 4 + (-4) = 0
Jadi titik potongnya (3,7) dan (-4,0)

Answer 2

Subtitusikan

4 + x = 16 - x²
x² + x + 4 - 16 = 0
x² + x - 12 = 0
(x - 2)(x + 3) = 0
x₁ = 2    x₂  = -3

x₁ = 2
y₁ = 4 + 2
y₁= 6

x₂ = -3
y₂ = 4 - 3
y₂ = 1

titik potongnya (2, 6) dan (-3, 1)