Question

Carilah titik balik Dr fungsi f(x) =x^3-12x

Answer 1

F(x) = x³ - 12x
f ' (x) = 3x² - 12
0      = 3(x + 2)(x - 2)
x = - 2 ⇒ y = (-2)³ - 12(-2) = 16
x = 2 ⇒ y = 2³ - 12(2) = - 16
titik balik: (-2,16) dan (2,-16)