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dy/dx = 2x
y = int 2x dx
= x² + c
masukan nilai x = 1 dan y = 3
3 = 1² + c
c = 2
persamaan kurvanya y = x² + 2
b) dy/dx = x - 1
y = (1/2)x² - x + c
x = 1 dan y = 3
3 = 1/2 - 1 + c
c = 7/2
y = (1/2)x² - x + 7/2
c) dy/dx = 3x - 1
y = (3/2)x² - x + c
x =1 dan y = 3
3 = 3/2 - 1 + c
c = 5/2
y = (3/2)x² - x + 5/2
d) dy/dx = x² - 1
y = (1/3)x³ - x + c
x = 1 dan y = 3
3 = 1/3 - 1 + c
c = 11/3
y = (1/3)x³ - x + 11/3