Question

Carilah nilai konstanta a pada setiap kesamaan berikut (x2+1) (x-5) + 3a =x3 - 5x2 +x+ 16

Answer 1

(x²+1) (x-5) + 3a = x³-5x²+x+16
x³-5x²+x-5 +3a = x³-5x²+x+16
x³-x³-5x²+5x²+x-x-5-16+3a =0
-5-16 = -3a
-21 = -3a
7 = a

semoga membantuu

Answer 2

Kalikan dulu
(x² + 1)(x - 5) + 3a = x³ - 5x² + x + 16
x³ - 5x² + x - 5 + 3a = x³ - 5x² + x + 16
samakan:
3a - 5 = 16
3a = 21
a = 7