Question

carilah nilai dari SIN 165°
menggunakan rumus Sin ( A ± B ) = Sin A x Cos B ± Cos A x Sin B​

Answer 1

Penjelasan dengan langkah-langkah:

Sin 165°

= Sin ( 30° + 135° )

= ((Sin 30°)(Cos 135°)) + ((Cos 30°)(Sin 165°))

= (1/2 × (-√2/2)) + ( √3/2 × √2/2 )

= -√2/4 + √6/4

[tex] = \frac{ - \sqrt{2} + \sqrt{6} }{4} \\ ≈ 0.258[/tex]