Question

Cari nilai x..
1) x^2-6x=5
2) 2x^2-3x=-5
pakai caraya pliss besok dikumpulkan

Answer 1

1.
x^2-6x-5=0
x=-b(+-)sqrt(b^2-4ac)/2a
x=6(+-)sqrt(36+20)/1
x=6(+-)sqrt(56)
x=6(+-) 2 sqrt(14)
x=6+2 sqrt(14) atau x=6-2 sqrt(14)

2.
2x^2-3x+5=0
x=-b(+-)sqrt(b^2-4ac)/2a
x=3(+-)sqrt(9-40)/4
x=3(+-)sqrt(-31)/4
x=3(+-) sqrt(31)i/4
x=(3+sqrt(31)i)/4 atau x=(3-sqrt(31)i)/4