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Verified answer
Materi : LogaritmaA = (³log36)² - (³log4)²
A = (³log36 + ³log4) (³log36 - ³log4)
A = (³log(36 . 4)) (³log(36/4))
A = (³log144) (³log9)
A = (³log(√12)⁴) (³log3²)
A = (4 . ³log√12) (2)
A = 8 . ³log√12
B = ³log√12
jadi A/B
= (8 . ³log√12) / (³log√12)
= 8