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log2/logx + log(3x-4)/logx = 2
log 2(3x - 4) / log x = 2
log 2(3x - 4) = 2 log x
log 2(3x - 4) = log x²
2(3x -4) = x²
6x - 8 = x²
x²-6x + 8 = 0
(x -4)(x-2) = 0
x1 = 4 dan x2 = 2
x1 > x2
sehingga
x1 - x2 = 4 - 2 = 2
Selamat belajar !
@Wello☺
ˣlog 2 (3x-4)= 2
ˣlog (6x-8)=2
6x-8=x²
x²-6x+8=0
rumus mencari x1-x2, jika x1>x2
x1-x2= √D / a
D= b²-4ac
D= (-6)²- 4. 1.8
D= 36-32
=4
maka, x1 - x2 = √D/a = √4/1 = 2