x = 10cm
opsi B
Diketahui :
segitiga ABC sama kaki AB = AC = x+2.
BC = 12cm.
keliling = 36cm.
Ditanya :
nilai x.
Pembahasan :
keliling segitiga = jumlah sisi sisinya.
CA + AB + BC =
(x+2) + (x+2) +12 = 36
2x+16 = 36
2x = 20
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x = 10cm
opsi B
Diketahui :
segitiga ABC sama kaki AB = AC = x+2.
BC = 12cm.
keliling = 36cm.
Ditanya :
nilai x.
Pembahasan :
keliling segitiga = jumlah sisi sisinya.
CA + AB + BC =
(x+2) + (x+2) +12 = 36
2x+16 = 36
2x = 20
x = 10cm