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Kapasitas ............... x .......................... y .................. 70
Bagasi .................... 12x ...................... 8y ................ 600
Harga ............... 500.000x ....... 400.000y ....... ?????
Model matematika
1) x + y ≤ 70
x = 0 => y = 70 => (0,70)
y = 0 => x = 70 => (70,0)
2) 12x + 8y ≤ 600 (:4) 3x + 2y ≤ 150
x = 0 => y = 75 => (0,75)
y = 0 => x = 50 => (50,0)
Titik potong
x + y = 70 |x3| 3x + 3y = 210
.......................... 3x + 2y = 150
---------------------------------------- -
...................................... y = 60
x + y = 70 => x = 70 - 60 = 10
Titik potong = (10,60)
Setelah digambar diperoleh titik sudut = (50,0), (0,70) dan (10,60)
Masukkan ke 500.000x + 400.000y
(50,0) => 500.000(50) + 400.000(0) = 25.000.000
(0,70) => 500.000(0) + 400.000(70) = 28.000.000
(10,60) => 500.000(10) + 400.000(60) = 5.000.000 + 24.000.000 = 29.000.000
Jadi nilai maksimumnya 29.000.000