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Jawaban :qair = m x c x DT= ( 250 ) x ( 4,2 ) x ( 35 – 25 )= 10.500 Jqbom = Cbom x DT= ( 75 ) x ( 35 – 25 )= 750 Jqreaksi = – (qair + qbom )qreaksi = - ( 10.500 J + 750 J )= - 11.250 J = – 11,25 kJ200 mg CH4 = 0,2 g CH4 = ( 0,2 / 16 ) mol = 0,0125 molDHc CH4 = ( – 11,25 kJ / 0,0125 mol ) = - 900 kJ / mol ( reaksi eksoterm )
ni contoh soal perhitungan kalorimeter + peembahasan,,semoga membantu..:D