September 2018 1 61 Report
Cara mengerjakan soal begini gimana ya?
1. Persamaan kuadrat  x^{2} + 6x + 3 = 0 mempunyai akar-akar  \alpha dan  \beta . Persamaan kuadrat yang akar-akarnya (3 \alpha +1) dan (3 \beta +1)adalah...........

a.  x^{2} -20x-46=0
b.  x^{2} -20x+46=0
c.  x^{2} -18x-46=0
d.  x^{2} + 18x+27=0
e.  x^{2} +20x+27=0

:)

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