Question

Cara menentukan biangan oksidasi dari unsur CuO,Cu2O, BaO2,SF6

Answer 1

1.CuO = 0 , O = -2
Cu + (-2) = 0
Cu = +2
2. Cu2O = 0
2Cu + (-2) = 0
Cu = +2/2= +1
3.BaO2 = 0 , Ba = +2
2 + 2O = 0
O = -2/2 = -1
4.SF6 = 0 , F = -1
S + 6(-1) = 0
S -6 =0
S = +6