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banyaknya posisi = k = 5
P(n,k) = n! / (n-k)!
P(5,5) = 5!/ (5-5)!
= 5! / (0)!
= 5! / 1
= 5! = 5 x 4 x 3 x 2 x 1 = 120
jadi cara memasang 5 bendera dalam 1 baris dapat dilakukan dengan 120 cara.