pOH= -logKb + log base/sal
pOH= - log (1.40 x10^-7) + log (0.5M)/(6.10M)
pOH= 6,853 + (- 1.086)
pOH= 5.767
pH + pOH =14
pH = 14- pOH
pH= 14 - 5.767
pH=8,23
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pOH= -logKb + log base/sal
pOH= - log (1.40 x10^-7) + log (0.5M)/(6.10M)
pOH= 6,853 + (- 1.086)
pOH= 5.767
pH + pOH =14
pH = 14- pOH
pH= 14 - 5.767
pH=8,23