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3x + 2y = 80
(2x+y)(-2)=8(-2)
3x+2y=80
-2(2x+y)2=-16
3x+2y=80
-(4x+2y)=-16
3x-2y=80
-4x-2y=-16
(3x+2y)+(-4x-2y)=80-16
-4x-2y=-16
3x+2y-4x-2y=64
-4x-2y=-16
-x=64
x= -64
sustituimos x en la primera ecuacion
-4x-2y=-16
-4(-64)-2y=-16
4*64-2y=-16
256-2y=-16
-2y+256=-16
-2y=-272
y =136
espero qte sirva suewrte y saludos