Respuesta:
Seja α o ángulo
[tex]a)tg\alpha =\frac{[-9-(-3)]}{[-8-(2)]}=\frac{-9+3}{-8-2} =\frac{-6}{-10} =\frac{3}{5}\implies \alpha =21,8\° \\\\b)tg\alpha =\frac{-6-(-4)}{10-0}=\frac{-2}{10} =-\frac{1}{5}\implies\alpha =348,7\°[/tex]
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Respuesta:
Seja α o ángulo
[tex]a)tg\alpha =\frac{[-9-(-3)]}{[-8-(2)]}=\frac{-9+3}{-8-2} =\frac{-6}{-10} =\frac{3}{5}\implies \alpha =21,8\° \\\\b)tg\alpha =\frac{-6-(-4)}{10-0}=\frac{-2}{10} =-\frac{1}{5}\implies\alpha =348,7\°[/tex]