calcula la gasolina que necesita un automóvil para recorrer 480 km si con 5 litros recorre 20 km
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【Rpta.】Para recorrer 20 km necesita 120 litros de gasolina.
[tex]{\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedimiento}}{\hspace{50pt}\above 1.2pt}[/tex]
Para este caso utilizaremos regla de tres simple directa, ya que ambas magnitudes(kilómetros y litros de gasolina) son directamente proporcionales.
Entonces
[tex]\mathsf{\:20\:km \ \ \xrightarrow{\hspace{90pt}} 5\:litros\ de\ gasolina}\\\mathsf{\:480\:km \xrightarrow{\hspace{90pt}} \boldsymbol{\mathsf{\ \ \ \ \ \ \ \ \ \ \ x}}}[/tex]
[tex]\mathsf{\hspace{1 pt}(20\:km)(x) =(5\:litros\ de\ gasolina)(480\:km)}\\\\\\\mathsf{\hspace{20 pt}x =\dfrac{(5\:litros\ de\ gasolina)(480\:km\hspace{-17pt}\dfrac{\hspace{0.5cm}}{~})}{(20\:km\hspace{-17pt}\dfrac{\hspace{0.5cm}}{~})}}\\\\\\\mathsf{\hspace{1 pt}\:\:\:\:\:\:\:\boxed{\boxed{\boldsymbol{\mathsf{x=120\: litros\ de\ gasolina}}}}}[/tex]
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[tex]\mathsf{\mathsf{\above 3pt \phantom{aa}\overset{\displaystyle \fbox{I\kern-3pt R}}{}\hspace{4 pt}\displaystyle \fbox{C\kern-6.5pt O}\hspace{4 pt}\overset{\displaystyle\fbox{C\kern-6.5pt G}}{} \hspace{4 pt} \displaystyle \fbox{I\kern-3pt H} \hspace{4pt}\overset{\displaystyle\fbox{I\kern-3pt E}}{} \hspace{4pt}\displaystyle \fbox{I\kern-3pt R} \phantom{aa}} \above 3pt}[/tex]