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Area = 50m² = L * L = L²
Diagonal = D
Lado = L
Area =
La diagonal del cuadrado divide al cuadrado en 2 triangulos rectangulos donde la diagonal es la hipotenusa.
Por Pitagoras
D² = L² + L²
D² = 2L² Pero L² = 50m²
D² = 2 * 50m²
D² = 100m²
D = √100m²
D = √10²m²
D = 10m
Respuesta.
La diagonal mide 10m