✌Rpta: El valor de "x - y" es - 5
[tex]\boldsymbol {\mathsf {Procedimiento}}[/tex]
Para resolver este ejercicio vamos a utilizar el metodo de igualación para encontrar los valores de "y" y "x"
[tex]\begin {gathered}\mathsf {\star \ {Primera \ ecuaci\acute{o}n \ despejamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x + y =7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x =7 - y}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {\star \ {Segunda \ ecuaci\acute{o}n \ despejamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5x - 2y =-7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5x =-7 + 2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x =\frac{-7 + 2y}{5} }\end {gathered}[/tex]
Ahora igualamos x = x
[tex]\begin {gathered}\mathsf {\star \ {Igualamos \ ecuaciones}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {7 - y = \frac{-7+2y}{5} }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5(7 - y) = -7+2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {35 - 5y = -7+2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {35 + 7 = 2y+5y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {42 = 7y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {\frac{42}{7} = y }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{6 = y }}} }\end {gathered}[/tex] ✔️
Ahora hallamos "x" reemplazando el valor de "y" en cualquiera de las dos ecuaciones, bueno elegimos la primera ecuación
[tex]\begin {gathered}\mathsf {\star \ {Hallamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x + 6 = 7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x = 7 - 6 }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{x = 1 }}} }\end {gathered}[/tex] ✔️
Nos piden hallar: "x -y"
[tex]\begin {gathered}\mathsf {\star \ {Hallamos \ X - Y}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {1-6 }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{-5 }}} }\end {gathered}[/tex] ✔️
No hay alternativa por lo tanto preguntale a tu profesor
Atentamente: [tex]\begin {gathered}\mathsf{\boxed{\bold {E}}_{\boxed {\bold {N}}}}\end {gathered}[/tex][tex]\begin {gathered}\mathsf{\boxed{\bold {V}}_{\boxed {\bold {E}}}}\end {gathered}[/tex][tex]\mathsf{\boxed {\bold{R}}}[/tex]
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✌Rpta: El valor de "x - y" es - 5
[tex]\boldsymbol {\mathsf {Procedimiento}}[/tex]
Para resolver este ejercicio vamos a utilizar el metodo de igualación para encontrar los valores de "y" y "x"
[tex]\begin {gathered}\mathsf {\star \ {Primera \ ecuaci\acute{o}n \ despejamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x + y =7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x =7 - y}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {\star \ {Segunda \ ecuaci\acute{o}n \ despejamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5x - 2y =-7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5x =-7 + 2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x =\frac{-7 + 2y}{5} }\end {gathered}[/tex]
Ahora igualamos x = x
[tex]\begin {gathered}\mathsf {\star \ {Igualamos \ ecuaciones}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {7 - y = \frac{-7+2y}{5} }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {5(7 - y) = -7+2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {35 - 5y = -7+2y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {35 + 7 = 2y+5y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {42 = 7y }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {\frac{42}{7} = y }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{6 = y }}} }\end {gathered}[/tex] ✔️
Ahora hallamos "x" reemplazando el valor de "y" en cualquiera de las dos ecuaciones, bueno elegimos la primera ecuación
[tex]\begin {gathered}\mathsf {\star \ {Hallamos \ X}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x + 6 = 7 }\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {x = 7 - 6 }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{x = 1 }}} }\end {gathered}[/tex] ✔️
Nos piden hallar: "x -y"
[tex]\begin {gathered}\mathsf {\star \ {Hallamos \ X - Y}}\end {gathered}[/tex]
[tex]\begin {gathered}\mathsf {1-6 }\end {gathered}[/tex]
[tex]\begin {gathered}\boldsymbol{\mathsf {\boxed{\boxed{-5 }}} }\end {gathered}[/tex] ✔️
No hay alternativa por lo tanto preguntale a tu profesor
Atentamente: [tex]\begin {gathered}\mathsf{\boxed{\bold {E}}_{\boxed {\bold {N}}}}\end {gathered}[/tex][tex]\begin {gathered}\mathsf{\boxed{\bold {V}}_{\boxed {\bold {E}}}}\end {gathered}[/tex][tex]\mathsf{\boxed {\bold{R}}}[/tex]