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pH = - log ( 0.125 )
pH = - ( - 0.903 )
pH = 0.903
b) pOH = - log [OH⁻]
pOH = - log ( 0.125 )
pOH = - ( 0.903 )
pOH + pH = 14
pH = 14 - 0.903
pH = 13.097