Respuesta:
[tex]h^{2} = a^{2} +b^{2} 26^{2} = 13^{2} + b^{2} \sqrt{676-169} =\sqrt{b^{2} } \\\\13\sqrt{3} =b[/tex]
Explicación paso a paso:
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Respuesta:
[tex]h^{2} = a^{2} +b^{2} 26^{2} = 13^{2} + b^{2} \sqrt{676-169} =\sqrt{b^{2} } \\\\13\sqrt{3} =b[/tex]
Explicación paso a paso: