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α = 0,000011/⁰C = 1,1 x 10⁻⁵/⁰C
ΔT = 45⁰ - 25⁰ = 20⁰C
Lt = Lo (1 + α • ΔT)
Lt = 2 (1 + 1,1 x 10⁻⁵ • 20)
Lt = 2 (1,00022)
Lt = 2,00044 m
Lt = 200,044 cm
Ok?
L₀ = 200 cm
ΔT = 45°C - 25°C = 20°C
α = 0,000011 /°C
- Ditanya : Lτ
- Penyelesaian :
Lτ = L₀ ( 1 + α × ΔT )
= 200 cm ( 1 + 0,000011 /°C × 20°C )
= 200 cm × 1,00022
= 200,044 cm