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luas akhir = Luas awal (1+(2α*Δt)
l akhir = 2(1+(0.000012*25*2)
L akhir = 4.0012 m²
A₀ = 2 m²
t₁ = 20°C
t₂ = 45°C
Δt = t₂-t₁
Δt =25°C
α = 1,2×10⁻⁵/°C
β = 2,4×10⁻⁵/°C
Dit = ΔA
Jwb=
ΔA = A₀.β.Δt
ΔA = 2.2,4×10⁻⁵.25
ΔA = 1,2×10⁻³ m²