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Δt = t₁ - to
= 390°C - 40°C
= 350°C
α = 0,000024/°C
Ditanyakan : a) ΔL
b) L₁
Penyelesaian : ΔL = α . Lo . Δt
= 0,000024 . 400 . 350
= 3,36 cm
L₁ = Lo + ΔL
= 400 cm + 3,36 cm
= 403,36 cm