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ΔL = L₁ - Lo
= 50,011 - 50
= 0,011 cm
to = 30°C
α = 0,000012/°C
Ditanyakan : t₁ (to + Δt)
Penyelesaian : Δt = ΔL : (Lo . α)
= 0,011 : (50 . 0,000012)
= 0,011 : 0,0006
= 18,33°C
t₁ = to + Δt
= 30 + 18,33
= 48,33
≈ 50°C