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ΔL= 0,038cm = 0,00038m
L₀=100cm = 1m
ΔT...............?
ΔL=L₀.α.ΔT
0,00038=1.0,000019.ΔT
0,00038/0,000019=ΔT
ΔT=20⁰C
jadi suhu yang diberikan adlah 20⁰C