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ΔL=0,33 mm→0,033cm
L0=100cm
t2=60°c
t1???
ΔL=L0. α . Δt
0,033=100 . 0,00011(t2-t1)
0,033=0,011(60-t1)
0,033=0,66-0,011t1
0,033-0,66=0,011t1
-0,627/