Penjelasan dengan langkah-langkah:
[tex](\frac{ \sqrt{25 \times \sqrt{9} } }{5} ) + \frac{x}{c} \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - \sqrt{900} } } }{ \sqrt{25 \times \sqrt{125} } }[/tex]
[tex](\frac{ \sqrt{25 \times \sqrt{9} } }{5} ) + \frac{24}{3} \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - \sqrt{900} } } }{ \sqrt{25 \times \sqrt{125} } }[/tex]
[tex](\frac{ \sqrt{25 \times 3 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - 30 } } }{ \sqrt{25 \times 5 } }[/tex]
[tex](\frac{ \sqrt{75 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - 30 } } }{ \sqrt{75 } }[/tex]
[tex](\frac{ \sqrt{75 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{482 } } }{ \sqrt{75 } }[/tex]
√25 x √9/5.+ 24/3 x √216 + 2/3 √512 - √900/√25 x √125
√25 x 9/5 + 8 x √216 + 2/3 x √512 - 30/√75
√75/5 + 8 x √216 + 2/3 x √512 - 30/√75
semoga bermanfaat
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Penjelasan dengan langkah-langkah:
[tex](\frac{ \sqrt{25 \times \sqrt{9} } }{5} ) + \frac{x}{c} \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - \sqrt{900} } } }{ \sqrt{25 \times \sqrt{125} } }[/tex]
[tex](\frac{ \sqrt{25 \times \sqrt{9} } }{5} ) + \frac{24}{3} \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - \sqrt{900} } } }{ \sqrt{25 \times \sqrt{125} } }[/tex]
[tex](\frac{ \sqrt{25 \times 3 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - 30 } } }{ \sqrt{25 \times 5 } }[/tex]
[tex](\frac{ \sqrt{75 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{512 - 30 } } }{ \sqrt{75 } }[/tex]
[tex](\frac{ \sqrt{75 } }{5} ) + 8 \times \frac{ \sqrt{216 + \frac{2}{3} \times \sqrt{482 } } }{ \sqrt{75 } }[/tex]
Penjelasan dengan langkah-langkah:
√25 x √9/5.+ 24/3 x √216 + 2/3 √512 - √900/√25 x √125
√25 x 9/5 + 8 x √216 + 2/3 x √512 - 30/√75
√75/5 + 8 x √216 + 2/3 x √512 - 30/√75
semoga bermanfaat