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(a-2)x²+(b-3)x+c+1 ≡ 2x²+4x+3
donde:
(a-2) = 2
a-2 = 2
a = 2+2
a = 4
(b-3) = 4
b-3 = 4
b = 4+3
b = 7
c + 1 = 3
c = 3 - 1
c = 2
Hallar: ab/c = (4)(7)/2 =28/2 = 14