Penjelasan:
diketahui :
a = 12 x 10^-6 /°c (0,000012)
panjang awal (L0) = 1.000 cm
∆T = 50°C
ditanya : penambahan panjang baja setelah di panaskan (L)
jawab :
L = L0 (1 + a ∆T)
L = 1.000 cm ( 1 + 0,000012 . 50°C)
L = 1.000 cm (1, 000012 . 50)
L = 1.000 cm ( 50,0006)
L = 50.000, 6 cm
semoga membantu
maaf kalau salah
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Penjelasan:
diketahui :
a = 12 x 10^-6 /°c (0,000012)
panjang awal (L0) = 1.000 cm
∆T = 50°C
ditanya : penambahan panjang baja setelah di panaskan (L)
jawab :
L = L0 (1 + a ∆T)
L = 1.000 cm ( 1 + 0,000012 . 50°C)
L = 1.000 cm (1, 000012 . 50)
L = 1.000 cm ( 50,0006)
L = 50.000, 6 cm
semoga membantu
maaf kalau salah