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T1 = 10°C
T2 = 60 °C
ΔT = T2 - T1 = 60 - 10 = 50°C
α = 0,00019/°C
dit: L2?
jawab:
°ΔL = α x L1 x ΔT
= 0,00019/°C x 2 x 50 = 0,019m
ΔL = L2 - L1
L2 = L1 + ΔL
= 2 + 0,019
= 2,019 m