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t₁= 25°C
Vo= 300 cm³
ΔV= 315-300= 15 cm³
= 0,001 /°C
Dit:
t₂=..?
Penye:
t₂= Δt+t₁
Δt= ΔV/(Vo.)
Δt= 15/(300×0,001)
Δt= 15/0,3
Δt= 50°C
t₂= 50+25
t₂= 75 °C