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lt = 400 cm = 4 m
α = 2×10⁻⁵/°C
t₁ = 70°C
t₂ = 200°C
Δt = t₂-t₁
Δt = 130
Jwb=
lt = l₀.(1+α.Δt )
4 = l₀. (1+2×10⁻⁵.130)
4 = l₀.(1+2,6×10⁻³)
4 = 1,0026 l₀
l₀ = 3,98 m