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a) 3 dm3 wodoru
mH2=2u
22,4dm3------2g
3dm3----------xg
x=0,27g
b) 1,5 dm3 tlenku siarki (vI)
mSO3=32u+3*16u=80u
22,4dm3------80g
1,5dm3--------xg
x=5,36g
c) 2,5 dm3 tlenku azotu (III)
mHNO2=1u+14u+2*16u=47u
22,4dm3------47g
2,5dm3--------xg
x=5,24g