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del dato, tenemos:
a+1+a/2 = ( a/5 + a+1 /11 )+13 , resolviendo:
3a/2 = 16a/55 + 12+1/11
165a - 32a / 110 = 133/11
133a /110 = 133/11 -------> a = 10
por lo tanto los números buscados serán: 10 y 11