Jawaban:
• n=1
BENAR
• n=k
• n=k+1
3 + 5 + 7 + ... + (2k + 1) + (2(k + 1) + 1) = (k + 1)((k + 1) + 2)
=> k(k+2) + 2k + 2 + 1 = (k+1)(k+3)
k² + 2k + 2k + 3 = (k+1)(k+3)
k² + 4k + 3 = (k+1)(k+3)
(k+1)(k+3) = (k+1)(k+3)
TERBUKTI
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Jawaban:
• n=1
BENAR
• n=k
BENAR
• n=k+1
3 + 5 + 7 + ... + (2k + 1) + (2(k + 1) + 1) = (k + 1)((k + 1) + 2)
=> k(k+2) + 2k + 2 + 1 = (k+1)(k+3)
k² + 2k + 2k + 3 = (k+1)(k+3)
k² + 4k + 3 = (k+1)(k+3)
(k+1)(k+3) = (k+1)(k+3)
TERBUKTI