Buktikan bahwa lim ⇒ 0 \frac{sin x}{x} = 1
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1 < x/sinx < 1/cosx
Jika x ⇒0 , maka 1/cosx ⇒ 1
L i m 1 < L i m x/sinx < L i m 1/cosx
x⇒0 x⇒0 x⇒0
Jadi, 1 < l i m x < 1
x⇒0 sin x
L i m x = 1
x⇒0 sin x
karena l i m x = 1 , maka L i m sin x = 1
x⇒0 sin x x⇒0 x