STeby
A log b+al log c=a log bc =a log b = x<=>b=a^x =a log c=y<=>c=a^y dengan mengalihkan nilai b dengan c maka b×c=a^x×a^y<=>b×c=a^x+y. (substitusi x dan y) =a log (b×c)=a log b+ a log c
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KevinDomenic
A log b + a log c = a log bc a log(b × c) = a log bc a log bc = a log bc
=a log b = x<=>b=a^x
=a log c=y<=>c=a^y
dengan mengalihkan nilai b dengan c maka
b×c=a^x×a^y<=>b×c=a^x+y. (substitusi x dan y)
=a log (b×c)=a log b+ a log c
a log(b × c) = a log bc
a log bc = a log bc