Question

buenas noches!

me podrian ayudar con estos ejercicios , les agradeceria muchísimo

Answer 1

Verified answer

PROBLEMA "a" :

[tex]B = ( {m}^{8} + (2m) {}^{0} - ( {m}^{5} \times {m}^{3} ) )\\ B = ( {m}^{8} + 1 - ( {m}^{5 + 3} )) \\ B = ( {m}^{8} + 1 - {m}^{8} ) \\ B = 1[/tex]

PROBLEMA "b" :

[tex]I = \frac{ {y}^{8} \times {y}^{8} \times {y}^{8} }{ {y}^{5} \times {y}^{7} } + \frac{ {x}^{9} \times {x}^{3} \times {x}^{2} }{ {x}^{5} \times {x}^{6} } \\ I = \frac{ {y}^{8 + 8 + 8} }{ {y}^{5 + 7} } + \frac{ {x}^{9 + 3 + 2} }{ {x}^{5 + 6} } \\ I = \frac{ {y}^{24} }{ {y}^{12} } + \frac{ {x}^{14} }{ {x}^{11} } \\ I = {y}^{24 - 12} + {x}^{14 - 11} \\ I = {y}^{12} + {x}^{3} [/tex]

PROBLEMA "c" :

[tex]E = \frac{(3 {m})^{6} \times (3m) {}^{8} \times (3m) {}^{2} }{(3m) {}^{5} \times (3m) } \\ E = \frac{(3m) {}^{6 + 8 + 2} }{(3m) {}^{5 + 1} } \\ E = \frac{(3m) {}^{16} }{(3m) {}^{6} } \\ E = (3m) {}^{16 - 6} \\ E = (3m) {}^{10} \\ E = 59049 {m}^{10} [/tex]

PROBLEMA "d" :

[tex]N = \frac{(9a) {}^{7} \times (5a) {}^{4} \times (5a) {}^{3} }{(5a) {}^{5} \times (5a) {}^{2} } \\ N = \frac{(9a) {}^{7} \times (5a) {}^{4 + 3} }{(5a) {}^{5 + 2} } \\ N = \frac{(9a) {}^{7} \times (5a) {}^{7} }{(5a) {}^{7} } \\ N = (9a) {}^{7} \\ N = 4782969 {a}^{7} [/tex]