Question

Bocil² ;-;


f(x) = x² + x! ÷ 2
f(3) = ...?
Pake cara ygy ​

Answer 1

Penjelasan dengan langkah-langkah:

f(x) = x² + x! ÷ 2

f(3) = 3² + 3! ÷ 2

f(3) = ( 3 × 3 ) + 3! ÷ 2

f(3) = 9 + 3! ÷ 2

f(3) = 9 + ( 3 × 2 × 1 ) ÷ 2

f(3) = 9 + ( 6 × 1 ) ÷ 2

f(3) = 9 + 6 ÷ 2

f(3) = 9 + 3

f(3) = 12

Answer 2

Penyelesaian :

• Diketahui :

• f(x) = x² + x! ÷ 2

• Ditanya :

• f(3) = ...

• Jawab :

• f(x) = x² + x! ÷ 2

• f(3) = 3² + 3! ÷ 2

• f(3) = ( 3 + 3 + 3 ) + 3! ÷ 2

• f(3) = ( 6 + 3 ) + 3! ÷ 2

• f(3) = 9 + 3! ÷ 2

• f(3) = 9 + ( 3 × 2 × 1 ) ÷ 2

• f(3) = 9 + ( 6 × 1 ) ÷ 2

• f(3) = 9 + 6 ÷ 2

• f(3) = 9 + ( 6 ÷ 2 )

• f(3) = 9 + 3

• f(3) = 12

• Kesimpulan :

• f(x) = x² + x! ÷ 2

• f(3) = ...

• Hasil nya adalah 12