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[tex] \frac{ \sqrt{64.2} - \sqrt{16.2} + \sqrt{4.2}}{ \sqrt{27} \sqrt{6} } = \frac{a}{b} \\ \frac{ 8\sqrt{2} -4 \sqrt{2} + 2\sqrt{2}} { \sqrt{27.6} } = \frac{a}{b} \\ \frac{(8-4+2) \sqrt{2} }{ \sqrt{162} } = \frac{a}