1) x² + 2x - 4 = 0
a = 1
b = 2
c = -4
ABC :
= -b ± √b² - 4ac/2a
= -2 ± √(2)² - 4(1(-4)/2(1)
= -2 ± √4 + 16/2
= -2 ± √20/2
= -2 ± 2√5/2
= 2(-1 ± 2√5)/2
x1 = 2(-1 + 2√5)/2 = -1 + 2√5
x2 = 2(-1 - 2√5)/2 = -1 - 2√5
catatan :
x² + 2x - 4 = 0 tidak dapat diselesaikan atau ditemukan faktor-faktor nya.
2) x² - 3x + 4 = 0
b = -3
c = 4
= 3 ± √(-3)² - 4(1(4)/2(1)
= (3 ± √9 - 16)/2
= (3 ± √-7)/2
= X€R
x² - 3x + 4 = 0 tidak dapat diselesaikan atau ditemukan faktor-faktor nya.
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Verified answer
1) x² + 2x - 4 = 0
a = 1
b = 2
c = -4
ABC :
= -b ± √b² - 4ac/2a
= -2 ± √(2)² - 4(1(-4)/2(1)
= -2 ± √4 + 16/2
= -2 ± √20/2
= -2 ± 2√5/2
= 2(-1 ± 2√5)/2
x1 = 2(-1 + 2√5)/2 = -1 + 2√5
x2 = 2(-1 - 2√5)/2 = -1 - 2√5
catatan :
x² + 2x - 4 = 0 tidak dapat diselesaikan atau ditemukan faktor-faktor nya.
2) x² - 3x + 4 = 0
a = 1
b = -3
c = 4
ABC :
= -b ± √b² - 4ac/2a
= 3 ± √(-3)² - 4(1(4)/2(1)
= (3 ± √9 - 16)/2
= (3 ± √-7)/2
= X€R
x² - 3x + 4 = 0 tidak dapat diselesaikan atau ditemukan faktor-faktor nya.