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Sifat-sifat sudut:
[tex]\begin{aligned} \angle SRP &= 180° - \angle RPQ \\&= 180° - (180° - \angle TSR) \\&= 180° - (180° - (\frac{180° - \angle TRS}{2})) \\&= 180° - (180° - (\frac{180° - 54°}{2})) \\&= 180° - 180° + \frac{180° - 54°}{2} \\&= \frac{126°}{2} \\&= 63° \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 01 - 04 - 2023}}[/tex]
N.F :
= (180 - (180 - (180 - 54) ÷ 2)°
= (180 - (180 - (126 ÷ 2)°
= (180 - (180 - 63)
= (180 - 117)
= 63°
[tex]\boxed { \color{cyan} \mathcal{INFINITE \: WORLD}}[/tex]
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Garis dan Sudut
..
Sifat-sifat sudut:
Penyelesaian Soal
[tex]\begin{aligned} \angle SRP &= 180° - \angle RPQ \\&= 180° - (180° - \angle TSR) \\&= 180° - (180° - (\frac{180° - \angle TRS}{2})) \\&= 180° - (180° - (\frac{180° - 54°}{2})) \\&= 180° - 180° + \frac{180° - 54°}{2} \\&= \frac{126°}{2} \\&= 63° \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 01 - 04 - 2023}}[/tex]
N.F :
= (180 - (180 - (180 - 54) ÷ 2)°
= (180 - (180 - (126 ÷ 2)°
= (180 - (180 - 63)
= (180 - 117)
= 63°
[tex]\boxed { \color{cyan} \mathcal{INFINITE \: WORLD}}[/tex]