Question

Bila p dan q akar-akar persamaan kuadrat x² + 5x + 3=0, maka nilai dari ( p - q )²=

Answer 1

P+q = -b/a = -5 pq = c/a = 3 (p-q)^2 = p^2 - 2pq + q^2 = [p^2 + q^2] -2pq = [(p+q)^2 - 2pq] -2pq = [(-5)^2 -2.3] -2.3 =[25-6] -6 = 13 ket: ^ = pangkat

Answer 2