Bila larutan CH3COOH 0,1 M memiliki ph = 3, maka larutan CH3COONa 0,1 M ph nya adalah ...... tolong ya pakai cara...
NadiaHipina
Ma = 0,1 M [G] = 0,1 M pH Asam = 3 [H+]= 10^-3 (H+) =Ka x Ma/Mg 10^-3= Ka x 0,1/0,1 Ka= 10^-3 (OH-)= √Kw/Ka x (G) [OH-]= √10^-14/10^-3 x 10^-1 [OH-]= √10^-12 [OH-]= 10^-6
[G] = 0,1 M
pH Asam = 3
[H+]= 10^-3
(H+) =Ka x Ma/Mg
10^-3= Ka x 0,1/0,1
Ka= 10^-3
(OH-)= √Kw/Ka x (G)
[OH-]= √10^-14/10^-3 x 10^-1
[OH-]= √10^-12
[OH-]= 10^-6
pOH = - log [OH-]
= - log 10^-6
= 6
pH= 14 - pOH
pH= 14-6
pH= 8
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