Bila a=3,b=0,c=-3 nilai dari[ax(b+c-a)]x(b+c) adalah
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b=0
c=-3
maka,
=[ax(b+c-a)]x(b+c)
=[3x(0+(-3)-3)]x(0+(-3))
=[3x(0-3-3)]x(0-3)
=[3x(-6)]x-3
=-18x-3
=54