Titik (x , y)
ax² + bx + c = y
a(0)² + b(0) + c = 10
c = 10
a(-1)² + b(-1) + c = 5
a - b + 10 = 5
a - b = -5 .............................. (1)
a(3)² + b(3) + c = 37
9a + 3b + 10 = 37
9a + 3b = 27
3a + b = 9 ............................ (2)
Eliminasi pers (2) dan (1):
3a + b = 9
a - b = -5
________+
4a = 4
a = 1
Subtitusi:
1 - b = -5
b = 6
y = x² + 6x + 10
Jadi, fungsi kuadrat tersebut adalah y = x² + 6x + 10.
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Fungsi Kuadrat
Titik (x , y)
ax² + bx + c = y
a(0)² + b(0) + c = 10
c = 10
a(-1)² + b(-1) + c = 5
a - b + 10 = 5
a - b = -5 .............................. (1)
a(3)² + b(3) + c = 37
9a + 3b + 10 = 37
9a + 3b = 27
3a + b = 9 ............................ (2)
Eliminasi pers (2) dan (1):
3a + b = 9
a - b = -5
________+
4a = 4
a = 1
Subtitusi:
a - b = -5
1 - b = -5
b = 6
ax² + bx + c = y
y = x² + 6x + 10
Jadi, fungsi kuadrat tersebut adalah y = x² + 6x + 10.