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Lo= 1 meter
Δt= 150-30= 120°C
α= 0,000012 /°C
Dit:
Lt=..?
Penye:
Lt= Lo.(1+α.Δt)
Lt= 1×(1+0,000012×120)
Lt= 1×(1+0,00144)
Lt= 1×1,00144
Lt= 1,00144 meter
L0 = 1m
Δt = ( t2 - t1 ) = ( 150 - 30 ) = 120· c
α = 0,000012/·c
jwb :
L = L0 ( 1 + α Δt )
= 1 ( 1+ 0,000012 x 120 )
= 1 ( 1,00144 )
= 1,00144 m